serious bit fiddling, div10 using shift magic
forgot that arm has no division (or respectively only later models have) many magic formulae out there, none seem to work 1000% on the interpreter. some big 0 ending numbers are 1 off.
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@ -9,20 +9,47 @@ class TestPutiRT < MiniTest::Test
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check_return m % 4
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end
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end
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def test_mod10
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[2,3,4,5,10,12,55].each do |m|
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@string_input = "return #{m}.mod10()"
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check_return m % 10
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# if you multiply i by "by" the return is the high 32 bits
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def high_times( i , by_high , by_low)
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by = by_high * 65536 + by_low
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by *= i
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by /= 65536
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by /= 65536
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return by
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end
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# if you multiply i by "by" the return is the low 32 bits
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def low_times( i , by_high , by_low)
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by = by_high * 65536 + by_low
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by *= i
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return (by & 0xffffffff)
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end
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def test_hightimes
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[2,3,4,5,10,121212 , 12345 , 3456 , 234567].each do |m|
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@string_input = "return #{m}.high_times(12 , 333)"
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check_return high_times(m,12,333)
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end
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end
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def test_lowtimes
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[2,3,4,5,10 , 3456 , 12345 , 121212 , 234567].each do |m|
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@string_input = "return #{m}.low_times(14 , 33)"
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check_return low_times(m,14,33)
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end
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end
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# finally settled on the long version in http://www.sciencezero.org/index.php?title=ARM:_Division_by_10
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# also the last looked good, but some bug is admittedly in all the ones i tried
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# (off course the bug is not included in the test, but easy to achieve with random numbers )
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# for high numbers with ending 0 they are all 1 low. Possibly Interpreter bug ?
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def test_div10
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[2,5,10,12 , 55 ].each do |m|
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[2,3,4,5,10 , 3456 , 12345 , 121212 , 234567].each do |m|
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@string_input = "return #{m}.div10()"
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check_return m / 10
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end
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end
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def test_as_char1
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@string_input = "return 5.as_char()"
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check_return 53
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