using compiler_for to create all building compilers

unify api, create defaults and especially pass the right types into the
typed method creation
This commit is contained in:
Torsten Ruger
2018-03-18 22:08:35 +05:30
parent e7b878a353
commit 0813312ddc
7 changed files with 27 additions and 25 deletions

View File

@ -22,10 +22,10 @@ module Risc
# create the method, do some checks and set it as the current method to be added to
# class_name and method_name are pretty clear, args are given as a ruby array
def self.create_method( class_name , method_name , args = {})
def self.create_method( class_name , method_name , args , frame )
raise "create_method #{class_name}.#{class_name.class}" unless class_name.is_a? Symbol
clazz = Parfait.object_space.get_class_by_name! class_name
create_method_for( clazz.instance_type , method_name , args)
create_method_for( clazz.instance_type , method_name , args , frame)
end
# create a method for the given type ( Parfait type object)
@ -33,11 +33,11 @@ module Risc
# args a hash that will be converted to a type
# the created method is set as the current and the given type too
# return the compiler (for chaining)
def self.create_method_for( type , method_name , args )
def self.create_method_for( type , method_name , args , frame)
raise "create_method #{type.inspect} is not a Type" unless type.is_a? Parfait::Type
raise "Args must be Hash #{args}" unless args.is_a?(Hash)
raise "Args must be Type #{args}" unless args.is_a?(Parfait::Type)
raise "create_method #{method_name}.#{method_name.class}" unless method_name.is_a? Symbol
method = type.create_method( method_name , args)
method = type.create_method( method_name , args , frame)
self.new(method)
end